1 class Solution {
2 public:
3 ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
4 // Start typing your C/C++ solution below
5 // DO NOT write int main() function
6 ListNode* root = new ListNode(-1);
7 ListNode* ptr = root;
8 while( l1!= NULL && l2 != NULL )
9 {
10 if( l1->val <= l2->val )
11 {
12 ptr->next = l1;
13 ptr = ptr->next;
14 l1 = l1->next;
15 }
16 else
17 {
18 ptr->next = l2;
19 ptr = ptr->next;
20 l2 = l2->next;
21 }
22 }
23 if( l1 != NULL )
24 ptr->next = l1;
25 if( l2 != NULL )
26 ptr->next = l2;
27
28 return root->next;
29
30 }
31 };
1 class Solution {
2 public:
3 ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
4 // Start typing your C/C++ solution below
5 // DO NOT write int main() function
6 if( !l1 && !l2 ) return NULL;
7 if( !l1 ) return l2;
8 if( !l2 ) return l1;
9 ListNode *h = new ListNode(0);
10
11 h -> next = l1;
12 ListNode *p = h;
13
14 while( l1 && l2 )
15 {
16 if( l1->val <= l2->val)
17 {
18 p = p->next;
19 l1 = l1->next;
20 }
21 else
22 {
23
24 p -> next = l2;
25 l2 = l2 -> next;
26 p -> next -> next = l1 ;
27 p = p->next;
28 }
29 }
30 if( l2 ) p->next = l2;
31 return h->next;
32
33 }
34 };
原文链接: https://www.cnblogs.com/jumpinGGrass/p/3171406.html
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